References

Move provides two types of references:

  • immutable & - cannot modify underlying values (or any of its fields).

  • mutable &mut - allow for modifications via a write through that reference.

Reference Operators:

Here the notation e: T stands for "expression e has type T".

SyntaxType Description

&e

&T where e: T and T is a non-reference type

Create an immutable reference to e

&mut e

&mut T where e: T and T is a non-reference type

Create a mutable reference to e.

&e.f

&T where e.f: T

Create an immutable reference to field f of struct e.

&mut e.f

&mut T where e.f: T

Create a mutable reference to field f of structe.

freeze(e)

&T where e: &mut T

Convert the mutable reference e into an immutable reference.

The &e.f and &mut e.f operators can be used both to create a new reference into a struct or to extend an existing reference:

let s = S { f: 10 };
let f_ref1: &u64 = &s.f; // works
let s_ref: &S = &s;
let f_ref2: &u64 = &s_ref.f // also works

A reference expression with multiple fields works as long as both structs are in the same module:

struct A { b: B }
struct B { c : u64 }
fun f(a: &A): &u64 {
  &a.b.c
}

Finally, note that references to references are not allowed:

let x = 7;
let y: &u64 = &x;
let z: &&u64 = &y; // will not compile

Reading and writing through references:

Both mutable and immutable references can be read to produce a copy of the referenced value.

Only mutable references can be written. A write *x = v discards the value previously stored in x and updates it with v.

SyntaxTypeDescription

*e

T where e is &T or &mut T

Read the value pointed to by e

*e1 = e2

() where e1: &mut T and e2: T

Update the value in e1 with e2.

Freeze inference:

A mutable reference can be used in a context where an immutable reference is expected:

let x = 7;
let y: &u64 = &mut x;

This works because the under the hood, the compiler inserts freeze instructions where they are needed.

More examples of freeze inference in action:

fun takes_immut_returns_immut(x: &u64): &u64 { x }

// freeze inference on return value
fun takes_mut_returns_immut(x: &mut u64): &u64 { x }

fun expression_examples() {
    let x = 0;
    let y = 0;
    takes_immut_returns_immut(&x); // no inference
    takes_immut_returns_immut(&mut x); // inferred freeze(&mut x)
    takes_mut_returns_immut(&mut x); // no inference

    assert!(&x == &mut y, 42); // inferred freeze(&mut y)
}

fun assignment_examples() {
    let x = 0;
    let y = 0;
    let imm_ref: &u64 = &x;

    imm_ref = &x; // no inference
    imm_ref = &mut y; // inferred freeze(&mut y)
}

Subtyping:

With this freeze inference, the Move type checker can view &mut T as a subtype of &T. As shown above, this means that anywhere for any expression where a &T value is used, a &mut T value can also be used. This terminology is used in error messages to concisely indicate that a &mut T was needed where a &T was supplied. For example

address 0x42 {
module example {
    fun read_and_assign(store: &mut u64, new_value: &u64) {
        *store = *new_value
    }

    fun subtype_examples() {
        let x: &u64 = &0;
        let y: &mut u64 = &mut 1;

        x = &mut 1; // valid
        y = &2; // invalid!

        read_and_assign(y, x); // valid
        read_and_assign(x, y); // invalid!
    }
}
}

will yield the following error messages

error:

    โ”Œโ”€โ”€ example.move:12:9 โ”€โ”€โ”€
    โ”‚
 12 โ”‚         y = &2; // invalid!
    โ”‚         ^ Invalid assignment to local 'y'
    ยท
 12 โ”‚         y = &2; // invalid!
    โ”‚             -- The type: '&{integer}'
    ยท
  9 โ”‚         let y: &mut u64 = &mut 1;
    โ”‚                -------- Is not a subtype of: '&mut u64'
    โ”‚

error:

    โ”Œโ”€โ”€ example.move:15:9 โ”€โ”€โ”€
    โ”‚
 15 โ”‚         read_and_assign(x, y); // invalid!
    โ”‚         ^^^^^^^^^^^^^^^^^^^^^ Invalid call of '0x42::example::read_and_assign'. Invalid argument for parameter 'store'
    ยท
  8 โ”‚         let x: &u64 = &0;
    โ”‚                ---- The type: '&u64'
    ยท
  3 โ”‚     fun read_and_assign(store: &mut u64, new_value: &u64) {
    โ”‚                                -------- Is not a subtype of: '&mut u64'
    โ”‚

The only other types currently that has subtyping are tuples.

Ownership:

Both mutable and immutable references can always be copied and extended even if there are existing copies or extensions of the same reference:

fun reference_copies(s: &mut S) {
  let s_copy1 = s; // ok
  let s_extension = &mut s.f; // also ok
  let s_copy2 = s; // still ok
  ...
}

This might be surprising for programmers familiar with Rust's ownership system, which would reject the code above. Move's type system is more permissive in its treatment of copies, but equally strict in ensuring unique ownership of mutable references before writes.

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